| Date: | Mon, 24 Apr 2006 11:35:55 +0300 |
| From: | Diomidis Spinellis <dds@aueb.gr> |
| Organization: | Athens University of Economics and Business |
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| Newsgroups: | comp.lang.c |
| Subject: | Re: C-Question |
| References: | <1145859100.543620.98850@i39g2000cwa.googlegroups.com> |
| In-Reply-To: | <1145859100.543620.98850@i39g2000cwa.googlegroups.com> |
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Remo wrote: > suppose if you have a 32 bit machine and your compiler supports upto 32 > bit. How can you store a number like > 789192378169245235656345633461249781623478112341234166 x 4 > into one variable. but this big number you can't store in any varible. > because our compiler supports upto 32 bit only. > > can any body plz answer to this question. log_2(789192378169245235656345633461249781623478112341234166*4) = 181.04, therefore the result requires 182 bits to store. If you are willing to sacrifice the least significant digits you can use the floating point representation. Otherwise, you might benefit from using an arbitrary precision library, like OpenSSL's bn. Most Linux and *BSD systems come with this library preinstalled; type "man 3 bn" for documentation. -- Diomidis Spinellis Code Quality: The Open Source Perspective (Addison-Wesley 2006) http://www.spinellis.gr/codequality?clc
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